A bag contains two red marbles and five blue marbles. you draw a marble, record its color, replace it, and then draw a second marble. what is the probability that you draw a blue marble at least once?
a.0.28
b.0.49
c.0.71
d.0.92

Respuesta :

2+5 = 5 total marbles

 5 are blue so you have a 5/7 chance of picking blue each time


5/7 = 0.714 rounded to 0.71

Answer: d. 0.92

Step-by-step explanation:

Given : Number of blue marbles in bag = 5

Number of red marbles in the bag = 2

Total marbles in bag= 5+2=7

Since,  we draw a marble, record its color, replace it, and then draw a second marble.

It means every outcome is independent of each other.

Now, the probability that you draw a blue marble at least once = 1- P(no blue marble drawn)

=[tex]1-\text{P(both marble are red)}\\\\=1-\dfrac{2}{7}\times\dfrac{2}{7}\\\\=1-\dfrac{4}{49}\\\\=\dfrac{49-4}{49}\\\\=\dfrac{45}{49}=0.918367346939\approx0.92[/tex]

Hence, the probability that you draw a blue marble at least once= 0.92

Hence, the correct answer is d. 0.92 .