I have provided a reaction that shows the diene which should be the starting material and how it reactions with one equivalent of HCl.
HCl undergoes an addition reaction in the presence of an alkene, and in this compound we have two double bonds. An alkene will attack the HCl molecule and the H+ atom will bond to the carbon with the most hydrogen atoms, in a Markovnikov fashion. The alkene that attacks is the one that leads to the most stable carbocation intermediate. This leads to a tertiary carbocation.
Since we are told to search for the kinetic product, we know that the carbocation formed will be the most stable, as shown. This leads to a product that has a double bond that is in the least stable position in the molecule, when compared to the thermodynamic product. The product of this reaction is shown in the attached image.
