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While heating two different samples of water at sea level, one boils at 102°c and one boils at 99.2°c. calculate the percent error for each sample from the theoretical 100.0°c?

Respuesta :

Kalahira
To find: Sample error in percent
 Solution:
 Formula:
((Experimental value-theoretical value)/theoretical value)*100
 where, theoretical value = 100°c
 and, experimental value = 102°c (sample 1) 99.2°c (sample 2)
 Sample error (in percentage) when boiling level was 102°c = ((102°c-100°c)/100°c)*100 = 2%
 Sample error (in percentage) when boiling level was 99.2°c = ((99.2°c-100°c)/100°c)*100 = -0.8%
ajeigbeibraheem

The percent error for sample 1 is 2%, The percent error for sample 2 is 0.8%

The percent error is defined as the percentage estimation between the difference of the actual value minus the theoretical value divided by the theoretical value.

Mathematically, we have:

[tex]\mathbf{Percent \ error = \dfrac{v_A - v_E}{v_E} \times 100\%}[/tex]

For sample 1:

[tex]\mathbf{Percent \ error = \dfrac{102 -100}{100} \times 100\%}[/tex]

[tex]\mathbf{Percent \ error = \dfrac{2 }{100} \times 100\%}[/tex]

Percent error = 2%

For sample 2:

[tex]\mathbf{Percent \ error = \dfrac{99.2 -100}{100} \times 100\%}[/tex]

[tex]\mathbf{Percent \ error =\Big| \dfrac{-0.8 }{100} \Big| \times 100\%}[/tex]

[tex]\mathbf{Percent \ error =0.80\%}[/tex]

Learn more about percent error here:

https://brainly.com/question/8145558?referrer=searchResults

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