The angular speed of the artificial satellite in the low orbit circling the earth every 98 minutes is 1.07 × 10⁻³rad/s.
Given the data in the question;
Period of the satellite; [tex]T = 98minutes = 5880s[/tex]
Angular speed; [tex]w = \ ?[/tex]
To determine the angular speed, we use the relation between angular speed and time period:
[tex]w = \frac{2\pi }{T}[/tex]
Where ω is the angular velocity and T is the time period in seconds.
We substitute our value into the equation
[tex]w = \frac{2\pi }{5880s} \\\\w = 1.07 * 10^{-3}rad/s[/tex]
Therefore, the angular speed of the artificial satellite in the low orbit circling the earth every 98 minutes is 1.07 × 10⁻³rad/s.
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