Respuesta :

the first one is x^2-4x+10
the second one is x^2+x+4
the third one is x^2-x+4
the last one is x^2-5x+16

Answer:


Step-by-step explanation:

We have been given Four options we will solve each one so as to write in rational or fractional form

CASE 1:

[tex](x-2)+\frac{6}{x-2}[/tex]

We will simplify by taking LCM we get:

[tex]\frac{(x-2)^2+6}{x-2}[/tex]

After further simplification:

[tex]\frac{x^2-4x+10}{x-2}[/tex]

Hence, Option 3 matches with 1.

CASE 2:

[tex](x+3)+\frac{10}{x-2}[/tex]

We will simplify by taking LCM we get:

[tex]\frac{(x-2)(x+3)+10}{x-2}[/tex]

After further simplification:

[tex]\frac{x^2+x+4}{x-2}[/tex]

Hence, Option 1 matches with 2.

CASE 3:

[tex](x+1)+\frac{6}{x-2}[/tex]

We will simplify by taking LCM we get:

[tex]\frac{(x-2)(x+1)+6}{x-2}[/tex]

After further simplification:

[tex]\frac{x^2-x+4}{x-2}[/tex]

Hence, Option 2 matches with 3.

CASE 4:

[tex](x-3)+\frac{10}{x-2}[/tex]

We will simplify by taking LCM we get:

[tex]\frac{(x-2)(x-3)+10}{x-2}[/tex]

After further simplification:

[tex]\frac{x^2-5x+16}{x-2}[/tex]

Hence, Option 4 matches with 4.