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The
correct answer is in file attached
we have
triangle RST
m∠R = 60, m∠S = 80 and m∠T=180-(80+60)=40
RS=4
triangle EFD
m∠F = 60, m∠D = 40 and m∠E=180-(60+40)=80
EF=4
Therefore
The triangles RST and EFD are congruents because they have two angles and the side common to them, respectively, equal.
This is the theorem of ASA (angle-side-angle).
Explication
Side common--------> RS=EF
Angles RS------------- > m∠R = 60 m∠S = 80
Angles EF------------- > m∠E = 80 m∠F = 60
The segment which is congruent to RT is FD, because angles of RT are 60 and 40, and angles of FD also are 60 and 40.
we have
triangle RST
m∠R = 60, m∠S = 80 and m∠T=180-(80+60)=40
RS=4
triangle EFD
m∠F = 60, m∠D = 40 and m∠E=180-(60+40)=80
EF=4
Therefore
The triangles RST and EFD are congruents because they have two angles and the side common to them, respectively, equal.
This is the theorem of ASA (angle-side-angle).
Explication
Side common--------> RS=EF
Angles RS------------- > m∠R = 60 m∠S = 80
Angles EF------------- > m∠E = 80 m∠F = 60
The segment which is congruent to RT is FD, because angles of RT are 60 and 40, and angles of FD also are 60 and 40.
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Similar triangles, may or may not be congruent.
The triangles are congruent by ASA
The given parameters are:
[tex]\mathbf{\triangle RST}[/tex]
[tex]\mathbf{\angle R = 60}[/tex]
[tex]\mathbf{\angle S = 80}[/tex]
[tex]\mathbf{RS = 4}[/tex]
[tex]\mathbf{\triangle EFD}[/tex]
[tex]\mathbf{\angle F = 60}[/tex]
[tex]\mathbf{\angle D = 40}[/tex]
[tex]\mathbf{EF = 4}[/tex]
The third angles of both triangles are:
[tex]\mathbf{\angle T = 180 - 60 - 80}[/tex]
[tex]\mathbf{\angle T = 40}[/tex]
[tex]\mathbf{\angle E = 180 - 60 -40}[/tex]
[tex]\mathbf{\angle E = 100}[/tex]
The above highlights mean that:
- The triangles have two congruent angles
- The triangles have one congruent side
This means that, the triangles are congruent by ASA
And the congruent sides are:
[tex]\mathb{RS = EF}[/tex]
Read more about congruent triangles at:
https://brainly.com/question/18799165