Respuesta :
Via synthetic division, we have
-3 | 1 8 19 12
... | -3 -15 -12
= = = = = = = = = = = =
... | 1 5 4 0
which is to say,
[tex]\dfrac{b^3+8b^2+19b+12}{b+3}=b^2+5b+4[/tex]
is the area of the base.
-3 | 1 8 19 12
... | -3 -15 -12
= = = = = = = = = = = =
... | 1 5 4 0
which is to say,
[tex]\dfrac{b^3+8b^2+19b+12}{b+3}=b^2+5b+4[/tex]
is the area of the base.
Answer:
Therefore, the area of the base will be (b² + 5b +4)
Step-by-step explanation:
The volume of rectangular prism has been given as (b³+8b²+19b+12) and height is (b+3) units.
We have to calculate the area of the base of the given prism
As we know the formula of volume of prism
⇒ V = (Area of the base) × Height
or Area of the base = V/ height
⇒ Area = [tex]\frac{(b^{3}+8b^{2}+19b+12) }{(b+3)}[/tex]
To solve this we will use synthetic division
-3 1 8 19 12
1 -3 -15 -12
1 5 4 0
Therefore, quotient of the division will be the area of the base,
which is (b²+5b+4)
Therefore, the area of the base will be (b² + 5b +4)