Hello!
So we have (x^2+4)^2+32=12x^2+48 and initial condition of a=x^2+4 and want it rewritten in terms of a and set equal to zero. So we have;
a^2+32=12(x^2+4) so now we have;
a^2+32=12a so now we just get everything on one side to set equal to zero;
a^2 -12a +32=0 is the final answer.
Hope this helps! Any questions please ask! Thank you so much!
