Respuesta :

According to Stefan-Boltzmann Law, the thermal energy radiated by a radiator per second per unit area is proportional to the fourth power of the absolute temperature. It is given by;
    P/A = σ T⁴ j/m²s 
Where; P is the power, A is the area in square Meters, T is temperature in kelvin and σ is the Stefan-Boltzmann constant, ( 5.67 × 10^-8 watt/m²K⁴)
Therefore;
Power/square meter = (5.67 × 10^-8) × (3000)⁴
                                 =  4.59 × 10^6 Watts/square meter
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Explanation:

we can calculate total  emitted power per square from Stefan-Boltzmann law

P = e σ AT⁴

where

P= power of body's thermal radiation

A= surface area of the body

σ= Stefan-Boltzmann constant it's value is  [tex]5.67 *10^-8 W/m^2k^4[/tex]

T= temperature of the body

e= emissivity of the substance here equal to 1

now by putting all the values in given formula

[tex]P/A= (1) (5.67*10^-8 W/m^2K^4)(3000)^4[/tex]

we get the answer

[tex]P/A= 4.5*10^ 6 W/m^2[/tex]

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