Hello!
This problem is asking for the equation of the line in slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept.
The question gives you the slope (-3/4), so you just have to find the y-intercept. You now have y = -3/4x + b.
The given point (4, -6) is an (x, y) point, meaning you can substitute those values for x and y into y = -3/4x + b; you'd then have:
-6 = -3/4(4) + b
-6 = -3 + b
-3 = b
And the y-intercept is -3! Now you just have to complete the equation with all the information. Your slope is -3/4 (given) and your y-int is -3, so the equation of the line is -
y = -3/4x - 3
Hope this helps!
