find the missing number in 3 4/5 divide [ ] = 2 5/7
Let the unknown number be x
[tex]\frac{3 \frac{4}{5}}{x}=2\frac{5}{7}[/tex]
[tex]3\frac{4}{5}[/tex] can be written as [tex]\frac{19}{5}[/tex]
[tex]2\frac{5}{7}[/tex] can be written as [tex]\frac{19}{7}[/tex]
So equation becomes
[tex]\frac{\frac{19}{5}}{x}=\frac{19}{7}[/tex]
We need to get x alone, so we multiply by x on both sides
[tex]\frac{19}{5}=\frac{19}{7} *x[/tex]
Now to remove 9/7 we take reciprocal and multiply it on both sides
[tex]\frac{19}{5} * \frac{7}{19} =\frac{19}{7}* \frac{7}{19} *x[/tex]
[tex]\frac{7}{5}=x[/tex]
The missing number is [tex]\frac{7}{5}[/tex]
