Respuesta :

[tex]\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \boxed{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k})\\\\ -------------------------------\\\\ y=x^2+4\implies y=1(x-\stackrel{h}{0})^2\stackrel{k}{+4}[/tex]

Otras preguntas