Which system of equations can you use to find the roots of the equation? x3 – 10x = x2 – 6 y = x3 – x2 + 10x + 6 y = 0 y = x3 – x2 + 10x y = 6 y = x3 – 10x y = x2 – 6

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Answer:

answer is:

[tex]y=x^{3}-10 x,y=x^{2}-6[/tex]

Step-by-step explanation:

we are asked to find which system of equations can we use to find the roots of the equation:

[tex]x^{3}-10x=x^{2}-6[/tex]

since the system of equation in last part is given as:

[tex]y=x^{3}-10 x,y=x^{2}-6[/tex]

so, on equating both the equations i.e. on equating both the values of 'y' we get the desired equation as:

[tex]x^{3}-10x=x^{2}-6[/tex].


The system of equations that can be used to find the roots of the equation [tex]{x^3} - 10x = {x^2} - 6[/tex] are [tex]\boxed{y = {x^3} - 10x{\text{ and }}y = {x^2} - 6}[/tex]. Option (c) is correct.

Further explanation:

Given:

The equation is [tex]{x^3} - 10x = {x^2} - 6.[/tex]

The options are as follows,

(a). [tex]y = {x^3} - {x^2} + 10x + 6{\text{ and }}y = 0[/tex]

(b). [tex]y = {x^3} - {x^2} + 10x {\text{ and }}y = 6[/tex]

(c). [tex]y = {x^3} - 10x{\text{ and }}y = {x^2} - 6[/tex]

Explanation:

The given equation is [tex]{x^3} - 10x = {x^2} - 6.[/tex]

The left hand side of the equation is [tex]{x^3} - 10x.[/tex]

The right hand side of the equation is [tex]{x^2} - 6.[/tex]

Consider the left hand side and right hand side as [tex]y[/tex].

[tex]y = {x^2} - 6[/tex] and [tex]y = {x^3} - 10x[/tex]

Hence, option (c) is correct.

The system of equations that can be used to find the roots of the equation  are [tex]\boxed{y = {x^3} - 10x{\text{ and }}y = {x^2} - 6}[/tex]. Option (c) is correct.

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Answer details:

Grade: High School

Subject: Mathematics

Chapter: Linear equation

Keywords: system of equations, roots, equation, x3-10x = x2-6, zeros, find the roots.