I have 24 pencils and 3 cups.the second cup holds one more pencil than the first.the third holds one more than the second.How many pencils does each cup contain

The first cup contains 7 pencils, the second cup contains 9 pencils, and the third cup contains 10 pencils and this can be determined by forming the linear equations.

Given :

I have 24 pencils and 3 cups.
The second cup holds one more pencil than the first.
The third holds one more than the second.

Let the number of pencils in the first cup be 'x', the second cup be 'y', and the third cup be 'z'. So, the total number of pencils is given by the equation:

x + y + z = 24 --- (1)

The linear equation that represents that the second cup holds one more pencil than the first is given by:

y = x + 1

x = y - 1 --- (2)

The linear equation that represents that the third holds one more than the second is given by:

z = y + 1 --- (3)

Now, substitute the values of 'z' and 'x' in equation (1).

y - 1 + y + y + 1 = 24

3y = 24

y = 8

Now, substitute the value of 'y' in equation (2) and equation (3).

x = 8 - 1

x = 7

z = 9 + 1

z = 10

So, the first cup contains 7 pencils, the second cup contains 9 pencils, and the third cup contains 10 pencils.

For more information, refer to the link given below:

https://brainly.com/question/11897796