Respuesta :
x + 6y = 2
4x - 3y = 10
The first thing to do when solving a system of equations using the addition/elimination method is to multiply one or both of the equation by a value that will cancel out one of the variable terms.
Based on this, the correct answer is D - multiply the bottom equation by 2 thus eliminating the y variable when the equations are added together:
x + 6y = 2 x + 6y = 2
2(4x - 3y = 10) --> 8x - 6y = 20
Hope this helps.
4x - 3y = 10
The first thing to do when solving a system of equations using the addition/elimination method is to multiply one or both of the equation by a value that will cancel out one of the variable terms.
Based on this, the correct answer is D - multiply the bottom equation by 2 thus eliminating the y variable when the equations are added together:
x + 6y = 2 x + 6y = 2
2(4x - 3y = 10) --> 8x - 6y = 20
Hope this helps.
The value of [tex]x = \frac{11}{3}[/tex] and [tex]y = \frac{-2}{27}[/tex].
The required equation is 4x = 10 + 3y.
The required value of y is [tex]y = \frac{6}{7}[/tex]
The required value of x is [tex]x = \frac{22}{9}[/tex]
Given that,
Equation are x + 6y = 2, 4x - 3y = 10
We have to find,
Solving this system of equations using the addition method.
According to the question,
- Add the equation first to get: 5x + 3y = 12 and then solve for x.
Then, x + 6y = 2, and 5x + 3y = 12
x + 6y = 2
x = 2 - 6y
Putting the value of x in the 2nd
5(2 - 6y) + 3y = 12
10 - 30y + 3y = 12
10 - 27y = 12
-27y = 12-10
-27y = 2
y = [tex]\frac{-2}{27}[/tex]
And the value of x.
[tex]x + 6y = 2\\x + 6(\frac{-2}{27}) = 2\\x + \frac{-12}{27} = 2\\27x - 12 = 54 \\27x = 66\\x = \frac{66}{27}\\x = \frac{11}{3}[/tex]
The value of [tex]x = \frac{11}{3}[/tex] and [tex]y = \frac{-2}{27}[/tex].
- Add -6y to both sides of the equation to isolate the x variable in the top equation.
x + 6y = 2, 4x - 3y = 10
Subtract -6y from both equation,
Then x + 6y - 6y = 2 - 6y
x = 2 - 6y
And 4x - 3y - 6y = 10 - 6y
4x - 9y = 10 - 6y
The required equation is 4x = 10 + 3y
- Multiply the top equation by 4 thus eliminating the x variable when the equations are added together.
4 ( x + 6y) = 4.2,
4x + 24y = 8
Adding equation 1 and 2 eliminate x
4x + 24y = 8
4x - 3y = 10
On adding the equation,
21y = 18
[tex]y = \frac{18}{21} \\y = \frac{6}{7}[/tex]
The required value of y is [tex]y = \frac{6}{7}[/tex]
- Multiply the bottom equation by 2 thus eliminating the y variable when the equations are added together.
4x - 3y = 10
Multiply by 2
2( 4x - 3y) = 2.10
8x - 6y = 20
Adding the equation and eliminate y ,
8x - 6y = 20
x + 6y = 2
On adding
9x = 22
[tex]x = \frac{22}{9}[/tex]
The required value of x is [tex]x = \frac{22}{9}[/tex]
For more information about System of equation click the link given below.
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