Respuesta :
Answer: The equation of the circle is
[tex]x^2+y^2+18.6x-8.2y+90.3=0.[/tex]
Step-by-step explanation: We are given to write the equation of the circle with radius √13 units and center at the point (-9.3, 4.1).
We know that
the standard equation of a circle with radius r units and center at the point (h, k) is given by
[tex](x-h)^2+(y-k)^2=r^2.[/tex]
In the given circle,
radius, r = √13 units and center, (h, k) = (-9.3, 4.1).
Therefore, the equation of the circle will be
[tex](x-(-9.3))^2+(y-4.1)^2=(\sqrt{13})^2\\\\\Rightarrow (x+9.3)^2+(y-4.1)^2=13\\\\\Rightarrow x^2+18.6y+86.49+y^2-8.2y+16.81=13\\\\\Rightarrow x^2+y^2+18.6x-8.2y+103.3=13\\\\\Rightarrow x^2+y^2+18.6x-8.2y+90.3=0.[/tex]
Thus, the equation of the circle is
[tex]x^2+y^2+18.6x-8.2y+90.3=0.[/tex]
Answer:
(x+9.3)2+(y−4.1) 2=13
Step-by-step explanation:
khan 20201 correct
