Respuesta :

Mon had 100 kg of water, dumped it into 10kg of pure salt, namely 100% salt, what happened?  well, it ended up with 100kg + 10kg, or 110kg of saline solution, off which 10kg are just salt.

so, if we take the 110kg to be the 100%, what is 10kg in percentage off of it?  namely the salty part.

[tex]\bf \begin{array}{ccll} amount&\%\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 110&100\\ 10&x \end{array}\implies \cfrac{110}{10}=\cfrac{100}{x}\implies x=\cfrac{10\cdot 100}{110}[/tex]
boffeemadrid

The kilograms of salt solution and the percentage of salt solution is required.

The mass of solution is 110 kg

The percentage of solution is 9.09%.

[tex]m_w[/tex] = Mass of water = 100 kg

[tex]m_s[/tex] = Mass of salt = 10 kg

Mass of solution

[tex]M=m_w+m_s\\\Rightarrow M=100+10\\\Rightarrow M=110\ \text{kg}[/tex]

Percentage salt solution

[tex]\dfrac{m_s}{M}\times 100\\ =\dfrac{10}{110}\times 100=9.09\%[/tex]

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