Solution:
It is given that , x = the number of cappuccino bottles and y = the number of café au lait bottles.
Let p ounces of coffee is mixed with q ounces of milk to make a bottle of cappuccino.
1. x = 6 p + 2 q
2. y = 4 p + 4 q
3. x + y ≥ 80
Amount of coffee possessed by manufacturer= 720 ounces
Amount of milk possessed by manufacturer= 400 ounces
Equation (1) gives
→6 p = 720
→→p=120 ounces(Number of bottles of coffee only)
→→→2 q = 400
→ q = 200 ounces(Number of bottles of milk only)
Maximum number of cappuccino bottles = 120
Equation (2) gives
→→4 p = 720
→ p = 180 ounces((Number of bottles of coffee only)
→→→ 4 q = 400
→→q = 100 ounces(Number of bottles of milk only)
Maximum number of Cafe au lait bottles = 100
So, x = The Maximum number of cappuccino bottles = 120
y=The Maximum number of café au lait bottles.=100
Also the manufacturer can try different combinations of Cappuccino and cafe au lait bottles of coffee to manufacture more than 80 bottles in a day. for example, (56,24), (34,46).....
