Respuesta :
Clarification to the question is that Mr. Gardener receives 8 and 1/3% (or 8.33%) interest annually.
The calculation is as follows
(money)(%interest) = interest
(300000)(8.33%) = interest
(300000)(0.0833) = interest
interest = 24990 or roughly 25000 anually
The calculation is as follows
(money)(%interest) = interest
(300000)(8.33%) = interest
(300000)(0.0833) = interest
interest = 24990 or roughly 25000 anually
$25,000
Further explanation
Given:
- Mr. gardener has $300,000 in his savings account.
- He receives 8¹/₃ % interest annually.
Question:
What interest (in dollars) does he receive annually?
The Process:
This problem includes the type of determining simple interest.
Simple interest = [tex]\boxed{ \ P \times r \times t \ }[/tex]
- P = principal (initial amount)
- r = annual interest rate
- t = time (in years)
The data is as follows:
- P = 300,000
- r = 8¹/₃ % or ²⁵/₃₀₀ or 0.0833
- t = 1 year
Let us calculate how much interest (in dollars) does he receive annually.
[tex]\boxed{ \ = 300,000 \times 8\frac{1}{3} \% \times 1 \ }[/tex]
[tex]\boxed{ \ = 300,000 \times \frac{25}{300} \ }[/tex]
[tex]\boxed{ \ = 1,000 \times 25 \ }[/tex]
[tex]\boxed{ \ = 25,000 \ }[/tex]
Thus the amount of interest does he receive annually equals $25,000.
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Notes
We must be able to distinguish between simple and compound interest. Please learn about this in the link attached below.
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