The area of a rectangular is (x^3-5x^2+3x-15), and the width of the rectangular is (x^2+3). If area = length x width, what is the length of the rectangle?
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Answer:
Option D. (x -5)
Step-by-step explanation:
Area of the rectangle is given as A = (x³ - 5x² + 3x - 15)
The width of the rectangle is W = (x² + 3)
Then we have to find the length (L) of the rectangle.
We know that area A = L× W
By putting the values of L and A
(x³- 5x² + 3x -15) = L× (x² + 3)
[tex]L=\frac{x^{3}-5x^{2}+3x-15}{x^{2}+3}[/tex]
Now we factorize the numerator first
(x³-5x²+3x-15) = x²(x - 5) + 3(x - 5) = (x² + 3)(x - 5)
Now [tex]L=\frac{(x^{2}+3)(x-5)}{x^{2}+3}=(x-5)[/tex]
Therefore Option D (x - 5) is the answer.