A paperboy rode his bike at 3 m/s. After being chased by a dog for 8 seconds, he was traveling 6m/s. What is his acceleration? Your answer

Respuesta :

a=vf-vi/tf-ti
a= velocity final-velocity initial / time final-time initial
a= 6 m/s - 3 m/s divided by 8 s - 0s 
a= 2 m/s / 8 m/s 
a= 1/4 m/s^2

Answer:

The acceleration is 0.4 m/s^2

Explanation:

The acceleration is given by the change of rate of the velocity in a range of time, so:

[tex]a=\frac{vf-vo}{t}\\where:\\vf=final\_velocity\\vo=initial\_velocity\\t=time[/tex]

[tex]a=\frac{6m/s-3m/s}{8s}=0.4m/s^2[/tex]