Respuesta :
a=vf-vi/tf-ti
a= velocity final-velocity initial / time final-time initial
a= 6 m/s - 3 m/s divided by 8 s - 0s
a= 2 m/s / 8 m/s
a= 1/4 m/s^2
a= velocity final-velocity initial / time final-time initial
a= 6 m/s - 3 m/s divided by 8 s - 0s
a= 2 m/s / 8 m/s
a= 1/4 m/s^2
Answer:
The acceleration is 0.4 m/s^2
Explanation:
The acceleration is given by the change of rate of the velocity in a range of time, so:
[tex]a=\frac{vf-vo}{t}\\where:\\vf=final\_velocity\\vo=initial\_velocity\\t=time[/tex]
[tex]a=\frac{6m/s-3m/s}{8s}=0.4m/s^2[/tex]