Respuesta :
Answer:
The correct answer is the first option: 7.5 ft by 30 ft.
Step-by-step explanation:
If a rectangle is enlarged by a certain factor, that means that its height and width are both enlarged by such a factor. The new dimensions of the rectangle are obtained by multiplying the old dimensions by the enlarging factor, therefor we can compute the new dimensions as:
[tex]W_N = W_O \cdot f[/tex]
[tex]H_N = H_O \cdot f[/tex]
Where [tex]W_N[/tex] is the new width, [tex]W_O[/tex] is the old width, [tex]H_N[/tex] is the new height, [tex]H_O[/tex] is the old height, and [tex]f[/tex] is the enlarging factor.
From the above we can finally get that:
[tex]W_N = 3 \cdot \frac{5}{2} = \frac{15}{2} = 7.5 ft[/tex]
[tex]H_N = 12 \cdot \frac{5}{2} = \frac{60}{2} = 30 ft[/tex]
Answer:
Option A) 7.5 ft by 30 ft
Step-by-step explanation:
We are given the following information:
Dimension of rectangle:
Length = 12 feet
Width = 3 feet
The poster is enlarged by a factor of [tex]\frac{5}{2}[/tex]
After enlargement, we can write
[tex]\text{Enlarged length} = \text{Original length}\times \text{Factor}\\\text{Length of Poster} = \text{Length of Rectangle}\times \displaystyle\frac{5}{2}\\\\\text{Length of Poster} = \frac{12\times 5}{2} = \frac{60}{2} = 30\text{ feet}\\\\\text{Width of Poster} = \text{Width of Rectangle}\times \displaystyle\frac{5}{2}\\\\\text{Width of Poster} = \frac{3\times 5}{2} = \frac{15}{2} = 7.5\text{ feet}[/tex]
The dimension of poster is 7.5 feet by 30 feet
Option A) 7.5 ft by 30 ft
