Answer:
Force that must be applied = 7.4556kgm/[tex]s^{2}[/tex] or 7.4556N
Explanation:
The relationship between coefficient of friction and force is
Coefficient of friction = frictional force/Normal reaction force
When a body moves at constant velocity, it means that the body is either at rest or it is moving without accelerating, in both case the acceleration is equal to zero (0)
Mass = 2.0kg, Coefficient of friction = .38, Force =?
Normal reaction = weight of the body
Weight = mass x acceleration due to free fall (since it wasn’t stated in the question we’ll take it to be 9.81m/[tex]s^{2}[/tex]
Weight = 2.0kg x 9.81m/[tex]s^{2}[/tex] = 19.62kgm/[tex]s^{2}[/tex]
:- Normal reaction = 19.62kgm/[tex]s^{2}[/tex]
Putting these values into the formula
.38 = Frictional force/ 19.62kgm/[tex]s^{2}[/tex]
Frictional force = 7.4556kgm/[tex]s^{2}[/tex]
Force that must be applied = Frictional force = 7.4556kgm/[tex]s^{2}[/tex]
This frictional force is the force that must be applied to the brick to make it move at a constant velocity any force greater than this value will overcome the frictional force hence the body accelerates.
