Respuesta :
f(x) = x² – 1
g(x) = 2x – 3
f(g(x))=(2x-3)²-1=(2x)²-2*2x*3+3²-1
f(g(x))=4x²-12x+8
The function has no undefined points or domain constraints. Therefore, the domain is -∞<x<+∞ or (-∞,+∞).
g(x) = 2x – 3
f(g(x))=(2x-3)²-1=(2x)²-2*2x*3+3²-1
f(g(x))=4x²-12x+8
The function has no undefined points or domain constraints. Therefore, the domain is -∞<x<+∞ or (-∞,+∞).