Respuesta :
The heat absorbed by the water that evaporates from the body is the so called latent vaporization heat of water.
The standard latent vaporization heat of water is 2,264.705 kJ / kg.
So, you just have to divide 125 kJ / 2,264.705 kJ/kg = 0.0552 kg = 55.2 g
Answer: 55.2 g
The standard latent vaporization heat of water is 2,264.705 kJ / kg.
So, you just have to divide 125 kJ / 2,264.705 kJ/kg = 0.0552 kg = 55.2 g
Answer: 55.2 g
Answer:
The mass of water evaporated is 55.31 g.
Explanation:
Latent heat of vaporization of water [tex]\Delta H_{vap}= 2260 J/g[/tex]
Mass of water evaporated = m
Change in temperature = ΔT = nil
Energy required to to evaporate the m mass of water present in sweat= Q
Q = 125 kJ = 125000 J
[tex]Q=\Delta H_{vap}\times m[/tex]
[tex]125000 J=2260 J/g\times m[/tex]
[tex]m=\frac{125000 J}{2260 J/g}=55.31 g[/tex]
The mass of water evaporated is 55.31 g.