Frequency of the pendulum F = 0.15Hz
Acceleration due to gravity g = 9.81 m/s^2
Period of the pendulum is calculated by T = 2 x 3.14 x squareroot of (L / g), L being the length of the pendulam.
We have an equation between T and F => T = 1 / F
T = 1 / 0.15 => T = 20 / 3
Now substituting the values
=> 20 / 3 = 2 x 3.14 x squareroot of (L / 9.81)
=> 3.33 = 3.14 x squareroot of (L / 9.81)
=> squareroot of (L / 9.81) = 3.33 / 3.14
=> L / 9.81 = 1.06^2
=> L = 1.13 x 9.81
Length of the pendulum = 11 m
