for the cylinder on the left-hand-side,
[tex]\bf \textit{surface area of a cylinder}\\\\
S=2\pi r(h+r)\quad
\begin{cases}
r=radius\\
h=height\\
------\\
h=10\\
r=5
\end{cases}\implies S=2\pi (5)(10+5)[/tex]
now, for the triangular prism on the right-hand-side,
notice is really just 2 triangles and 3 rectangles, stacked up to each other at the edges.
the triangles have a base of 4, and a height of 1.5.
the rectangle on the left and the one on the right is a 6x2.5 rectangle.
the rectangle at the bottom, is a 4x6 rectangle.
adding their areas, is the area of the prism,
[tex]\bf \stackrel{two~triangles}{2\left[\cfrac{1}{2}(4)(1.5) \right]}+\stackrel{left-right~rectangles}{2(6\cdot 2.5)}+\stackrel{bottom~rectangle}{4\cdot 6}
\\\\\\
6~~+~~30~~+~~24[/tex]
