Answer:
P(student plays both basketball or football)=18/25
Step-by-step explanation:
We are given that:
In a group of 25 students, 12 students play basketball, 11 students play football. Five students play both sports.
Now, A student is chosen randomly from this group.
What is the probability that the student plays both basketball or football?
Probability of any event=no. of favorable outcomes/total no. of outcomes
Here, no. of favorable outcomes
=no. of students who plays both basketball or football
= 12+11-5
= 18
and, total no. of outcomes=25
Hence, P(student plays both basketball or football)=18/25
