GG1256
contestada

How many liters of oxygen can react with 84.0 grams of lithium metal at standard temperature and pressure? Show all of the work used to find the answer.

Equation: 4Li + O2--> 2Li2O

Respuesta :

voidless
  60. 4Li(s) + O2(g) >>>>>>>>>>> 2Li2O(s) 

moles O2 required = (84 grams Li) * (1 mol Li / 6.941 grams Li) * (1 mol O2 / 4 mol Li) = 3.026 moles O2 required. 

PV = nRT, P = 1 atm, V = ?, n = 3.026 moles, R = 0.0821 L*atm/mol*K, T = 273 K 
(1 atm)*(V) = (3.026 moles O2) * (0.0821 L*atm/mol*K) * (273 K) 
V = 67.82 Liters is the answer. 

hope this helps