What is the perimeter of the figure in the diagram (round to three decimal places if necessary)?
A) 44
B) 36.472
C) 36
D) 28.472

What is the perimeter of the figure in the diagram round to three decimal places if necessary A 44 B 36472 C 36 D 28472 class=

Respuesta :

Perimeter (p) = length around a shape.
So any horizontal sides we can add based upon their length in x-values and any vertical sides we can add based upon their length in y-values. The diagonal sides we can find by the distance formula:
[tex]d = \sqrt{( {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } [/tex]
So the bottom base goes from x=1 to x=8, then up 1, right 1, and up from y=3 to y=9, then left from x=9 to x=6, down from y=9 to y=6, left from x=6 to x=3.
So far that is: (8-1)+1+1+(9-3)+(9-6)+(9-6)+(6-3)
= 7+2+6+3+3+3 = 24
Now for the diagonal:
[tex]d = \sqrt{( {(x2 - x1)}^{2} + {(y2 - y1)}^{2}) } \\ = \sqrt{( {(3- 1)}^{2} + {(6 - 2)}^{2} )} \\ = \sqrt{( {2}^{2} + {4}^{2} )} = \sqrt{(4 + 16)} \\ = \sqrt{20} = 2 \sqrt{5} = 4.47[/tex]
P = 24 + 4.47 = 28.47
D) 28.472

Answer: 28.472

Step-by-step explanation: You need to find the length of all the outside edges. For the triangles you will need to use the Pythagorean Theorem. The perimeter is 28.472