The volume of carbon dioxide produced has been 5.6 L. Thus, option B is correct.
The moles have been defined as the mass of the substance with respect to the molar mass.
The moles have been expressed as:
[tex]\rm Moles=\dfrac{Mass}{Molar\;mass} [/tex]
The balanced chemical equation for the formation of carbon dioxide has been:
[tex]\rm CaCO_3\;\rightarrow\;CaO\;+\;CO_2[/tex]
The available mass of calcium carbonate has been 25 g.
The molar mass of calcium carbonate has been 100 g/mol
Substituting the values for the moles of calcium carbonate:
[tex]\rm Moles=\dfrac{25}{100} \\ Moles=0.25\;mol[/tex]
The available moles of calcium carbonate has been 0.25 mol.
According to the balanced chemical equation, 1 mole of calcium carbonate produces 1 mole of carbon dioxide.
The moles of carbon dioxide produced has been:
[tex]\rm 1\;mol\;CaCO_3=1\;mol\;CO_2\\
0.25\;mol\;CaCO_3=0.25\;mol\;CO_2[/tex]
The moles of carbon dioxide produced has been 0.25 mol.
From the ideal gas, the volume of 1 mol of gas has been 22.4 L.
The volume of 0.25 mol carbon dioxide has been:
[tex]\rm 1\;mol\;CO_2=22.4\;L\\ 0.25\;mol\;CO_2=0.25\;\times\;22.4\;L\\ 0.25\;mol\;CO_2=5.6\;L[/tex]
The volume of carbon dioxide produced has been 5.6 L. Thus, option B is correct.
Learn more about volume of gas, here:
https://brainly.com/question/13970341
