Respuesta :
Q= c m T (T is the change in time)
C= Q/(mT)
= 266/(0.015kg x 25)
C=709.33 J/kg.C
C= Q/(mT)
= 266/(0.015kg x 25)
C=709.33 J/kg.C
Answer:
[tex]c=0.709\ J/g\ ^{\circ} C[/tex]
Explanation:
Given that,
Heat required to raise the temperature, Q = 266 J
Mass, m = 15 g
Temperature, [tex]\Delta T=25^{\circ}\ C[/tex]
To find,
The specific heat of graphite.
Solution,
The formula for the specific heat is given by :
[tex]Q=mc\Delta T[/tex]
[tex]c=\dfrac{Q}{m\Delta T}[/tex]
[tex]c=\dfrac{266\ J}{15\times 25}[/tex]
[tex]c=0.709\ J/g\ ^{\circ} C[/tex]
So, the specific heat capacity of graphite is [tex]0.709\ J/g\ ^{\circ} C[/tex]. Hence, this is the required solution.
