This question involves the concepts of angular momentum and linear speed.
The angular momentum of the record is "8.57 x 10⁻⁴ J.s".
The angular momentum of the record can be given by the following formula:
[tex]L =mvr[/tex]
where,
- L = angular momentum = ?
- m = mass = 0.013 kg
- v = linear speed = rω
- r = radius = 15 cm = 0.15 m
- ω = angular speed = (28 rpm)[tex](\frac{2\pi\ rad}{1\ rev})(\frac{1\ min}{60\ s})[/tex] = 2.93 rad/s
Therefore,
[tex]L=m(r\omega)r=mr^2\omega\\
L = (0.013\ kg)(0.15\ m)^2(2.93\ rad/s)[/tex]
L = 8.57 x 10⁻⁴ J.s
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