Answer:
Option A is correct
[tex]x = \frac{1}{6}y^2[/tex]
Step-by-step explanation:
From the figure, we can see that the equation of the graph is a horizontal parabola.
The equation of the horizontal parabola opens to the right is given by:
[tex]x = a(y-k)^2+h[/tex] .....[1]
where:
(h, k) is the vertex of the parabola .
Given that:
(0, 0) = (h, k)
⇒h = k = 0
Substitute in [1] we get;
[tex]x = a(y-0)^2+0[/tex]
[tex]x = ay^2[/tex]
Therefore, the answer from the given option is [tex]x = \frac{1}{6}y^2[/tex]
