kristasearles
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Points B, D, and F are midpoints of the sides of triangle ACE. EC = 38 and DF = 16. Find AC. The diagram is not to scale.

For my answer I put 32 because df is parallel to ce and e is the midpoint of ca so I multiplied 16 by 2 to get 32

Is this correct? Thank you :)

Points B D and F are midpoints of the sides of triangle ACE EC 38 and DF 16 Find AC The diagram is not to scale For my answer I put 32 because df is parallel to class=

Respuesta :

You are correct. DF is half as long as AC since DF is the parallel midsegment to AC

AC = 2*DF
AC = 2*16
AC = 32

The info about EC = 38 is extra info most likely put in there to throw you off, or as a distraction.

Points D and F are the midpoints of sides EC and AE respectively therefore, DF is parallel to AC and hence, AC is twice of DF. So the value of side AC is equal to 32.

Given :

  • Triangle ACE
  • Side, EC = 38
  • B is the midpoint of AC.
  • D is the midpoint of EC.
  • F is the midpoint of AE.
  • DF = 16.

It is given that F is the midpoint of AE and D is the midpoint of EC and therefore, DF is parallel to AC.

If DF is parallel to AC than AC is twice of DF and it is given that DF = 16. Therefore, AC = 32.

[tex]\rm AC =2\times DF[/tex]

[tex]\rm AC = 2\times 16[/tex]

[tex]\rm AC = 32[/tex]

Therefore, it can be conclude that if points B, D, and F are the midpoints of the sides of triangle ACE than DF is parallel to AC and AC = [tex]\rm 2\times DF = 32[/tex] .

For more information, refer the link given below:

https://brainly.com/question/24580745

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