Respuesta :

[tex]\bf \begin{array}{ccll} miles&hour\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 2&\frac{2}{5}\\\\ 11&h \end{array}\implies \cfrac{2}{11}=\cfrac{\quad \frac{2}{5}\quad }{h}\implies \cfrac{2}{11}=\cfrac{\quad \frac{2}{5}\quad }{\frac{h}{1}} \\\\\\ \cfrac{2}{11}=\cfrac{2}{5}\cdot \cfrac{1}{h}\implies \cfrac{2}{11}=\cfrac{2}{5h}\implies 10h=22\implies h=\cfrac{22}{10} \\\\\\ h=\cfrac{11}{5}\implies h=2\frac{1}{5}[/tex]