Respuesta :
The initial concentration of H2SO4 is 10M
Given that, it has a constant number of moles.
We can say n=n
So C1xV1=C2xV2
where C is concentration and V is volume
This gives us V1=(C2V2)/C1=0.2L
So we need 0.2ml of 10M H2SO4
(We add 3.8L of distilled water to reach 4L)
M is a unit of concentration and can be written as mol/L
Given that, it has a constant number of moles.
We can say n=n
So C1xV1=C2xV2
where C is concentration and V is volume
This gives us V1=(C2V2)/C1=0.2L
So we need 0.2ml of 10M H2SO4
(We add 3.8L of distilled water to reach 4L)
M is a unit of concentration and can be written as mol/L
Considering the definition of diution, 0.2 L of 10.0 M H₂SO₄ is required to prepare 4.0 L of 0.50 M H₂SO₄.
First, you have to know that dilution is the reduction in concentration of a chemical in a solution. So, dilution is the procedure followed to prepare a less concentrated solution from a more concentrated one, and it simply consists of adding more solvent.
In a dilution, the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume of the solution increases.
To prepare a dilution, a certain volume of the concentrated solution is taken, and it is taken to a container, adding diluent until the volume calculated for the diluted solution is reached.
The expression to prepare a solution is the following:
Ci×Vi= Cf×Vf
Where:
- Ci = initial concentration of the solution.
- Vi = Initial volume of the solution.
- Cf = final concentration of the solution.
- Vf = Final volume of the solution.
In this case:
- Ci= 10 M
- Vi= ?
- Cf= 0.50 M
- Vf= 4 L
Replacing in the dilution expression:
10 M×Vi= 0.50 M× 4 L
Solving:
[tex]Vi= \frac{0.50 Mx 4 L}{10 M}[/tex]
Vi= 0.2 L
Finally, 0.2 L of 10.0 M H₂SO₄ is required to prepare 4.0 L of 0.50 M H₂SO₄.
Learn more about dilution:
- brainly.com/question/20113402?referrer=searchResults
- brainly.com/question/22762236?referrer=searchResults