A ray in the emission spectrum has a wavelength of 3.10 x 1014 meters. Given that the speed of light is 2.998 x 108 m/s, what is the frequency of the ray?

a. 0.967 x 10-6 HZ
b. 9.2938 x 10-7 HZ
c. 0.967 x 10-5 HZ
d. 9.2938 x 107 HZ

Respuesta :

Catya
Frequency has units of Hz which is s^-1

m/s * (1/m) = 1/s
"E" stands for the magnitude x10^
2.998 E8   m/s * ( 1 wave / 3.10 E14 m) = 9.67 E-7

frequency = 9.67 x 10^-7 Hz
move the decimal place to the left and you're looking at solution A.

Answer: The correct answer is option a.

Explanation:

To calculate the frequency of the ray, we use the formula:

[tex]\nu=\frac{c}{\lambda}[/tex]

where,

[tex]\nu[/tex] = Frequency of the ray = ? Hz

c = Speed of light = [tex]2.998\times 10^8m/s[/tex]

[tex]\lambda[/tex] = Wavelength of the ray = [tex]3.10\times 10^{14}m[/tex]

Putting values in above equation, we get:

[tex]\nu=\frac{2.998\times 10^8m/s}{3.10\times 10^{14}m}\\\\\nu=0.967\times 10^{-6}s^{-1}=0.967\times 10^{-6}Hz[/tex]

Hence, the correct answer is Option a.