Answer:
[tex]\boxed{B\:\:\:864\:units^2}[/tex]
Step-by-step explanation:
The surface area of the regular pyramid is the sum of the area of the 4 triangular faces and the area of the square base.
The area of the triangular faces is
[tex]=4\times \frac{1}{2}\times base\times height[/tex]
[tex]=4\times \frac{1}{2}\times 16\times 19[/tex]
[tex]=2\times 16\times 19[/tex]
[tex]=608\:units^2[/tex]
The area of the square base
[tex]=l^2[/tex]
[tex]=16^2[/tex]
[tex]=256\:units^2[/tex]
The surface area of the regular polygon is therefore;
[tex]=608+256[/tex]
[tex]=864\:units^2[/tex]
