Respuesta :

budwilkins
Since we need a point that divides K-->J into two segments in a 1:3 ratio, let's flip it to a 3:1 ratio in the J-->K direction. That means that this point is 3/(3+1) = 3/4 of the way up line JK.
Let's take 3/4 of the x of K (plus the 1 for the x of J):
3/4×(9 - 1) + 1 (because the beginning ofvthe line, at J, has an x of 1)...
3/4×(8) + 1 = 6 + 1 = 7
Therefore the answer is C) 7
calculista

Step 1

Find the distance KJ in the x-coordinate

we know that

the distance between two points with only one coordinate is equal to

[tex]d=\left|x_2-x_1\right|[/tex]

substitute the values

[tex]d=\left|9-1\right|=8\ units[/tex]

Step 2

Find the x-coordinate of the point  that divides the directed line segment from K to J into a ratio of [tex]1:3[/tex]

we know that

the ratio is [tex]1:3[/tex]

so

[tex]1+3=4[/tex]

Divided the distance  KJ in the x-coordinate by [tex]4[/tex]

[tex]8/4=2\ units[/tex]

Adds the x-coordinate of J to  [tex]3[/tex] times  [tex]2\ units[/tex]

[tex]1+3*(2)=7\ units[/tex]

therefore

the answer is the option

[tex]7\ units[/tex]

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