Of the elements: B, C, F, Li, and Na, the chemical element with the highest ionization energy is Florine (F) with 1681 eV.
Ionization energy can be defined as the minimum energy required to remove or detach an electron from a neutral atom in its gaseous state.
Generally, ionization energy tend to increase from left to right across a period on the periodic table and from bottom to top in each group of a periodic table.
An increase in the ionization energy of chemical elements is mainly because the atomic radius of chemical elements generally decreases across the periodic table, typically from alkali metals (group 1 elements) such as sodium, lithium and hydrogen to noble gases (group 8 elements) such as neon, helium, and argon.
Given these elements:
- Boron (B): its ionization energy is 800.9 eV.
- Carbon (C): its ionization energy is 1086 eV.
- Florine (F): its ionization energy is 1681 eV.
- Sodium (Na): its ionization energy is 496 eV.
- Lithium (Li): its ionization energy is 520 eV.
In conclusion, we can deduce that the chemical element with the highest ionization energy is Florine (F) with 1681 eV.
Read more: https://brainly.com/question/22313655
