Lets get the negative reciprocal of the slope so we get
[tex]m = \frac{1}{2} [/tex]
Now the equation that is perpendicular is
[tex]y = \frac{1}{2} x + b[/tex]
Lets solve for b by plugging in the point (x,y)=(6,1)
[tex]1 = \frac{1}{2} (6) + b \\ 1 = 3 + b \\ 1 - 3 = b \\ b = - 2[/tex]
Now plug that into the equation. So the equation of the line that is perpendicular and
passes through the point (6, 1) is
[tex]y = \frac{1}{2} x - 2[/tex]
