Respuesta :
The answer would be . Since we are looking for the spring constant you would need to use the formula
[tex]PEs = \frac{1}{2} k {x}^{2} [/tex]
. Then you'd substitute, for PEs and x.
[tex]10j=1/2k(.20m^2).[/tex]
Then solve. k=500n/m
[tex]PEs = \frac{1}{2} k {x}^{2} [/tex]
. Then you'd substitute, for PEs and x.
[tex]10j=1/2k(.20m^2).[/tex]
Then solve. k=500n/m
The spring constant of the spring is 500 N/m
From the question given above, the following data were obtained:
- Energy (E) = 10 J
- Compression (e) = 0.2 m
- Spring constant (K) =?
The spring constant, K can be obtained as follow:
E = ½Ke²
10 = ½ × K × 0.2²
10 = ½ × K × 0. 04
10 = K × 0.02
Divide both side by 0.02
K = 10 / 0.02
K = 500 N/m
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