A spring stores 10. joules of elastic potential
energy when it is compressed 0.20 meter. What
is the spring constant of the spring?

Respuesta :

The answer would be . Since we are looking for the spring constant you would need to use the formula
[tex]PEs = \frac{1}{2} k {x}^{2} [/tex]
. Then you'd substitute, for PEs and x.
[tex]10j=1/2k(.20m^2).[/tex]
Then solve. k=500n/m

The spring constant of the spring is 500 N/m

From the question given above, the following data were obtained:

  • Energy (E) = 10 J
  • Compression (e) = 0.2 m
  • Spring constant (K) =?

The spring constant, K can be obtained as follow:

E = ½Ke²

10 = ½ × K × 0.2²

10 = ½ × K × 0. 04

10 = K × 0.02

Divide both side by 0.02

K = 10 / 0.02

K = 500 N/m

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