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A particle moves with velocity function v(t) = 2t2 - 3t - 3, with v measured in feet per second and t measured in seconds. Find the acceleration of the particle at time t = 2 seconds. (4 points)

a. 3/4 ft/s^2
b. -1 ft/s^2
c. 32ft/s^2
d. 5 ft/s^2

Respuesta :

Answer:

d. 5 ft/s^2

Step-by-step explanation:

The acceleration is the derivative of the velocity.

In this problem, we have the velocity function

[tex]v(t) = 2t^{2} - 3t -3[/tex]

So the acceleration function is:

[tex]a(t) = v^{\prime}(t) = 4t - 3[/tex].

Find the acceleration of the particle at time t = 2 seconds

This is a(2). So:

[tex]a(2) = v^{\prime}(2) = 4(2) - 3 = 5[/tex].

The correct answer is

d. 5 ft/s^2

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