2(x+3)2+12(x+3)2+1Reorder the right side of the equation to match the vertex form of a parabola.y=2(x+3)2+1y=2(x+3)2+1Use the vertex form, y=a(x−h)2+ky=a(x-h)2+k, to determine the values of aa, hh, and kk.a=2a=2h=−3h=-3k=1k=1Find the vertex (h,k)(h,k).(−3,1) ...................................
