Cosine of ∠C has the value of [tex]\frac{7}{25}[/tex]. Option (1) will be the answer.
By applying Pythagoras theorem in right angle ΔABC,
[tex](\text{Hypotenuse)}^2=(\text{leg 1)}^2+(\text{leg 2)}^2[/tex]
AC² = AB² + BC²
(25)² = (24)² + BC²
BC = [tex]\sqrt{(25)^2-(24)^2}[/tex]
= [tex]\sqrt{625-576}[/tex]
= [tex]\sqrt{49}[/tex]
= 7
Since, [tex]\text{cos}(\theta)=\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]
Therefore, cos(C) = [tex]\frac{BC}{AC}=\frac{7}{25}[/tex]
Hence, Option (1) will be the correct answer.
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