Answer:
54.2 m/s
Explanation:
We can solve the problem by using the law of conservation of energy. The total mechanical energy at the top of the hill is just gravitational potential energy:
[tex]E_i = mgh[/tex]
where m is the mass of the bobsled, g is the gravitational acceleration and h=150 m. The total mechanical energy at the bottom of the hill is just kinetic energy:
[tex]E_f = \frac{1}{2}mv^2[/tex]
where v is the velocity of the bobsled at the bottom of the hill. Since the total energy must be conserved, we can write:
[tex]mgh=\frac{1}{2}mv^2[/tex]
and we can solve for v
[tex]v=\sqrt{2gh}=\sqrt{2(9.81 m/s^2)(150 m)}=54.2 m/s[/tex]
