Applying the numeric values, it is found that these following ordered pairs lie on the graph of the function [tex]f(x) = 128(0.5)^x[/tex]:
(1,64), (3,16) and (8,0.5).
Verifying if point (0,1) lies on the graph:
[tex]f(0) = 128(0.5)^0 = 128(1) = 128[/tex]
Since [tex]f(0) \neq 1[/tex], point (0,1) does not lie on the graph of the function.
Now, for point (1,64):
[tex]f(1) = 128(0.5)^1 = 64[/tex]
Since [tex]f(1) = 64[/tex], point (1,64) lies on the graph of the function.
For point (3,16):
[tex]f(3) = 128(0.5)^3 = \frac{128}{8} = 16[/tex]
Since [tex]f(3) = 16[/tex], point (3,16) lies on the graph of the function.
Finally, for point (8,0.5):
[tex]f(8) = 128(0.5)^8 = \frac{128}{256} = 0.5[/tex]
Since [tex]f(8) = 256[/tex], point (8,0.5) lies on the graph of the function.
A similar problem is given at https://brainly.com/question/11657085