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Object E has a mass of 4,800 kilograms. Object F has a mass of 600 kilograms. Both objects were placed on different planets so that their weights are equal.

The gravity acting on Object E is ________ times the gravity acting on Object F.

A) 1⁄8

B) 1⁄4

C) 1

D) 8

Respuesta :

the answer is 8 because 4800 divided by 600 equals 8 so the right answer is d

Answer:

Option A

Explanation:

Mass of object E [tex]= 4,800[/tex] kilogram

Mass of object E [tex]= 600[/tex] kilogram

Let the gravity of planet on which object E is placed [tex]= g_{1}[/tex]

Gravity of planet on which object F is placed [tex]= g_{2}[/tex]

As we know -

Weight is equal to the product of mass and gravity.

The weight of both the objects is same after they are placed on planets with different gravity.

[tex]M_{E} * g_{1} = M_{F} * g_{2} \\\frac{M_{E}}{M_{F}} = \frac{g_{2}}{g_{1}} \\[/tex]

Substituting the given values in above equation, we get -

[tex]\frac{4800}{600} = \frac{g_{2}}{g_{1}} \\\frac{g_{2}}{g_{1}} = 8[/tex]

Thus,  gravity acting on Object E is ___[tex]\frac{1}{8}[/tex]_____ times the gravity acting on Object F.