To know if he would make it, he must reach a distance of 3.5km at his take off speed which is 196m/s
So distance S = (v^2sin2theta)/g
We want to know the man's distance if he leaves at that speed. So we have
S = ((196)^2 sin(2*30))/9.8
S = 38416 sin 60 / 9.8
S = 33269.231/9.8
S = 3394.819m which is 3.39km or 3.4 when approximately. Will he make it? No, he won't.